8085 Programming

8085 Assembly Language Programs & Explanations1. Statement
: Store the data byte 32H into memory location 4000H.

Program 1:

MVI A, 32H : Store 32H in the accumulator

STA 4000H : Copy accumulator contents at address 4000H HLT : Terminate program execution

Program 2:

PROGRAM TO LOAD  A WITH 30H ,B WITH 44H ,H WITH 93H.

ANS:

ALOGRITHM:

STEP 1: LOAD  A WITH 30H
 STEP 2: LOAD B WITH 44H
STEP 3:LOAD H WITH 93H
STEP 4: STOP

MVI  A, 30H  ;  (LOAD  A WITH 30H)
MVI  B,44H ;   (LOAD B WITH 44H)
MVI H,93H ;(lOAD  H WITH 93H)
HLT   ;

Program 3:

LOAD B  AND C WITH DATA BYTES 65H AND 87H  .  ADD B WITH C, AND STORE RESULT IN B.

ANS:

ALGORITHM:

STEP 1: LOAD B REG. WITH 65H
STEP 2: LOAD C REG. WITH 87H
STEP 3: LOAD ACCUMULATOR  WITH B REG.
STEP 4:ADD  A REG WITH B REG.
STEP 5: STORE RESULT IN B REGISTER.
STEP 6: STOP.
PROGRAM :
   MVI  B,   65H   ; LOAD  B REG. WITH 65H
MVI    C,   87H ; LOAD C REG. WITH 87H
MOV  A,   B    ;  LOAD  A REG. WITH B REG.
ADD  C   ;    A REG <---A  REG.+ B REG.
MOV  B,  A   ; STORE RESULT IN B REG.
HLT   ;  STOP

Program 4:
ADD  THE CONTENTS OF TWO MEMORY LOCATIONS D000H AND D0001H. STORE RESULT IN MEMORY LOCATION D002H.

ALGORITHM :

STEP 1: LOAD FIRST   NUMBER FROM MEMORY LOCATION D000H.

STEP 2:LOAD  SECOND NUMBER FROM  MEMORY LOCATION D001H.

STEP 3:ADD FIRST  NUMBER  WITH SECOND NUMBERS.

STEP 4: STORE RESULT  TO MEMORY  LOCATION  D002H.

STEP 5: STOP.

PROGRAM :

LDA D000H  ; LOAD FIRST NUMBER FROM D000H IN A REG.
MOV  B, A   ; COPY  IT TO B REG.
LDA  D001H  ; LOAD SECOND NUMBER FROM D001H IN
ADD  B      ;  LOAD   A REG.<---A REG. + B REG.
STA  D002H; STORE RESULT  AT MEMORY LOCATION D002H
HLT     ;



write a program addition of two 16-bit  numbers:

Program - 5.a: Add two 16-bit numbers - Source Program 1

Sample problem:

(4000H) = 15H
(4001H) = 1CH
(4002H) = B7H
(4003H) = 5AH
Result = 1C15 + 5AB7H = 76CCH
(4004H) = CCH
(4005H) = 76H

Source Program 1:
LHLD 4000H                : Get first I6-bit number in HL
XCHG                        : Save first I6-bit number in DE
LHLD 4002H                : Get second I6-bit number in HL
MOV A, E                : Get lower byte of the first number
ADD L                        : Add lower byte of the second number
MOV L, A                : Store result in L register
MOV A, D                : Get higher byte of the first number
ADC H                        : Add higher byte of the second number with CARRY
MOV H, A                : Store result in H register
SHLD 4004H                : Store I6-bit result in memory locations 4004H and 4005H.
HLT                        : Terminate program execution